![]() ![]() SetTimeout() accepts time in milliseconds, so setTimeout(fn, 1000) tells JavaScript to call fn after 1 second. To transform seconds into milliseconds you will need to multiply your seconds by 1000. Be sure to check browser support as this is a language feature introduced with ECMAScript 6. To complete this task, first of all, you will need to transform seconds into milliseconds. 14 Answers Sorted by: 534 Browser Here's a solution using the new async/await syntax. setTimeout () accepts time in milliseconds, so setTimeout (fn, 1000) tells JavaScript to call fn after 1 second. Luckily for us, JavaScript provides a few ways for a developer to wait X seconds before executing the next line of the code. To delay a function execution in JavaScript by 1 second, wrap a promise execution inside a function and wrap the Promise's resolve() in a setTimeout() as shown below. To delay a function execution in JavaScript by 1 second, wrap a promise execution inside a function and wrap the Promise's resolve () in a setTimeout () as shown below.
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